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Relations and Functions (Class 12)

JEE Main 2024 (Online) 30th January Evening ShiftMCQEasy📈 Topic in 22% papers+4−1
Ques. 1JEE Main 2024, 30 January (Evening Shift)

Let f: R-\0\ R be a function satisfying f ( xy )= f(x)f(y) for all x,y,f(y) 0. If f'(1)=2024, then

  1. xf'(x)+2024f(x)=0
  2. xf'(x)-2023f(x)=0
  3. xf'(x)-2024f(x)=0
  4. xf'(x)+f(x)=2024

Answer

(3) xf'(x)-2024f(x)=0

Solution

Differentiate w.r.t. x (keep y constant): 1yf' ( xy )= f'(x)f(y)

Put y=x: f'(1)x= f'(x)f(x) 2024x= f'(x)f(x)

∴ xf'(x)-2024f(x)=0

Answer: (3)

Keep practising — Relations and Functions (Class 12)

Ques. 2JEE Main 2024, 30 January (Evening Shift)

The number of symmetric relations defined on the set \1,2,3,4\ which are not reflexive is .

Ques. 3JEE Main 2024, 29 January (Morning Shift)

Let R be a relation on Z Z defined by (a, b)R(c, d) if and only if ad-bc is divisible by 5. Then R is

  1. Reflexive and transitive but not symmetric
  2. Reflexive and symmetric but not transitive
  3. Reflexive but neither symmetric nor transitive
  4. Reflexive, symmetric and transitive
Ques. 4JEE Main 2024, 29 January (Morning Shift)

If f(x)= cases2+2x, & -1 x<0\ 1- x3, & 0 x 3 cases; g(x)= cases-x, & -3 x 0\ x, & 0<x 1 cases, then range of (f g)(x) is

  1. [0,1)
  2. [0,3)
  3. (0,1]
  4. [0,1]
Ques. 5JEE Main 2024, 29 January (Evening Shift)

If R is the smallest equivalence relation on the set \1,2,3,4\ such that \(1,2),(1,3)\ , then the number of elements in R is .

  1. 15
  2. 10
  3. 12
  4. 8
Ques. 6JEE Main 2024, 27 January (Morning Shift)

Let S=\1,2,3, ,10\. Suppose M is the set of all the subsets of S, then the relation R=\(A, B):A B ; A, B M\ is :

  1. symmetric only
  2. reflexive only
  3. symmetric and reflexive only
  4. symmetric and transitive only
Ques. 7JEE Main 2024, 27 January (Morning Shift)

The function f:N-\1\ ; defined by f(n)= the highest prime factor of n, is :

  1. one-one only
  2. neither one-one nor onto
  3. onto only
  4. both one-one and onto
Ques. 8JEE Main 2024, 27 January (Evening Shift)

Let f:R- \ -12 \ and g:R- \ -52 \ be defined as f(x)= 2x+32x+1 and g(x)= |x|+12x+5. Then, the domain of the function fog is :

  1. R- \- 74 \
  2. R
  3. R- \- 52,- 74 \
  4. R- \- 52 \

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