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Laws of Motion · Question 68

AIPMT 2001MCQEasy📈 Topic in 25% papers+4−1
1

A 1 kg stationary bomb is exploded in three parts having mass 1 : 1 : 3 respectively. The parts having the same mass move in perpendicular directions with velocity 30 m/s, then the velocity of the bigger part will be

  1. 10 2 m/s
  2. 10 2 m/s
  3. 15 2 m/s
  4. 15 2 m/s

Answer

(1) 10 2 m/s

Solution

Masses: 15 kg, 15 kg and 35 kg

Momentum of each small part = 0.2 30 = 6 kg m/s, at right angles

Resultant momentum of the two = 62 + 62 = 6 2 kg m/s

Initial momentum is zero, the bigger part has equal and opposite momentum.

0.6 v = 6 2

v = 10 2 m/s

Answer: (1)

AIPMT 2001

Keep practising — Laws of Motion

2

A body of mass 3 kg hits a wall at an angle of 60 and returns at the same angle. The impact time was 0.2 s. The force exerted on the wall is [figure]

  1. 150 3 N
  2. 50 3 N
  3. 100 N
  4. 75 3 N
AIPMT 2000
3

Two masses as shown in the figure are suspended from a massless pulley. The acceleration of the system when masses are left free is [figure]

  1. 2g3
  2. g3
  3. g9
  4. g7
AIPMT 2000
4

A mass of 1 kg is thrown up with a velocity of 100 m/s. After 5 seconds, it explodes into two parts. One part of mass 400 g comes down with a velocity 25 m/s. The velocity of other part is (Take g = 10 m s-2)

  1. 40 m/s
  2. 50 m/s
  3. 100 m/s
  4. 60 m/s
AIPMT 2000

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