A mass of 1 kg is thrown up with a velocity of 100 m/s. After 5 seconds, it explodes into two parts. One part of mass 400 g comes down with a velocity 25 m/s. The velocity of other part is (Take g = 10 m s-2)
- 40 m/s
- 50 m/s
- 100 m/s
- 60 m/s
Answer
(3) 100 m/s
Solution
Velocity just before explosion: v = u - gt = 100 - 10 5 = 50 m/s (upward)
Momentum is conserved in the explosion (taking upward as positive):
1 50 = 0.4 (-25) + 0.6 v'
0.6 v' = 60
v' = 100 m/s (upward)
Answer: (3)