If pH of a saturated solution of Ba(OH)2 is 12, the value of its Ksp is
- 4.00 10-6 M3
- 4.00 10-7 M3
- 5.00 10-6 M3
- 5.00 10-7 M3
Answer
(4) 5.00 10-7 M3
Solution
pH = 12 pOH = 2 [OH-] = 10-2 M
Ba(OH)2(s) Ba2+(aq) + 2OH-(aq)
[ Ba2+] = 12[OH-] = 5 10-3 M
Ksp = [ Ba2+][OH-]2
= (5 10-3)(10-2)2
= 5.00 10-7 M3
Answer: (4)