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Solutions · Question 25

AIPMT 2015MCQEasy📈 Topic in 25% papers+4−1
1

What is the mole fraction of the solute in a 1.00 m aqueous solution?

  1. 1.770
  2. 0.0354
  3. 0.0177
  4. 0.177

Answer

(3) 0.0177

Solution

1.00 m ⇒ 1 mol solute in 1000 g of water.

Moles of water = 100018 = 55.56 mol

⇒ xsolute = 11 + 55.56

= 156.56

= 0.0177

Answer: (3)

AIPMT 2015

Keep practising — Solutions

2

The boiling point of 0.2 mol kg-1 solution of X in water is greater than equimolal solution of Y in water. Which one of the following statements is true in this case?

  1. Molecular mass of X is less than the molecular mass of Y.
  2. Y is undergoing dissociation in water while X undergoes no change.
  3. X is undergoing dissociation in water.
  4. Molecular mass of X is greater than the molecular mass of Y.
AIPMT 2015 (Cancelled)
3

Which one of the following electrolytes has the same value of van't Hoff factor (i) as that of Al2(SO4)3 (if all are 100% ionised)?

  1. Al(NO3)3
  2. K4[Fe(CN)6]
  3. K2SO4
  4. K3[Fe(CN)6]
AIPMT 2015 (Cancelled)
4

Which of them is not equal to zero for an ideal solution?

  1. Vmix
  2. P = Pobserved - PRaoult
  3. Hmix
  4. Smix
AIPMT 2015 (Cancelled)
5

Of the following 0.10 m aqueous solutions, which one will exhibit the largest freezing point depression?

  1. KCl
  2. C6H12O6
  3. Al2(SO4)3
  4. K2SO4
AIPMT 2014
6

Which condition is not satisfied by an ideal solution?

  1. mixV = 0
  2. mixS = 0
  3. Obeyance to Raoult's Law
  4. mixH = 0
NEET 2013 (Karnataka)
7

Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2) at 25 are 200 mm Hg and 41.5 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at the same temperature will be (Molecular mass of CHCl3 = 119.5 u and molecular mass of CH2Cl2 = 85 u)

  1. 173.9 mm Hg
  2. 615.0 mm Hg
  3. 90.6 mm Hg
  4. 285.5 mm Hg
AIPMT 2012 (Mains)
8

pA and pB are the vapour pressures of pure liquid components, A and B, respectively of an ideal binary solution. If xA represents the mole fraction of component A, the total pressure of the solution will be

  1. pA + xA (pB - pA )
  2. pA + xA (pA - pB )
  3. pB + xA (pB - pA )
  4. pB + xA (pA - pB )
AIPMT 2012 (Prelims)
9

A 0.1 molal aqueous solution of a weak acid is 30% ionized. If Kf for water is 1.86 C/m, the freezing point of the solution will be

  1. -0.18 C
  2. -0.54 C
  3. -0.36 C
  4. -0.24 C
AIPMT 2011 (Mains)
10

200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57 10-3 bar. The molar mass of protein will be (R = 0.083 L bar mol-1 K-1)

  1. 51022 g mol-1
  2. 122044 g mol-1
  3. 31011 g mol-1
  4. 61038 g mol-1
AIPMT 2011 (Mains)
11

The freezing point depression constant for water is 1.86 C m-1. If 5.00 g Na2SO4 is dissolved in 45.0 g H2O, the freezing point is changed by -3.82 C. Calculate the van't Hoff factor for Na2SO4.

  1. 2.05
  2. 2.63
  3. 3.11
  4. 0.381
AIPMT 2011 (Prelims)

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