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Relations and Functions · Question 15

JEE Main 2025 (Online) 3rd April Morning ShiftMCQMedium📈 Topic in 35% papers+4−1
1

If the domain of the function f(x) = e ( 2x-35+4x ) + -1 ( 4+3x2-x ) is [ , ), then 2 + 4 is equal to

  1. 4
  2. 3
  3. 7
  4. 5

Answer

(1) 4

Solution

For e: 2x-35+4x > 0

⇒ x < - 54 or x > 32 … (i)

For -1: -1 4+3x2-x 1, x 2

4+3x2-x 1 ⇒ 4x+22-x 0 ⇒ x - 12 or x > 2

4+3x2-x -1 ⇒ 2x+62-x 0 ⇒ -3 x < 2

⇒ -3 x - 12 … (ii)

From (i) and (ii): domain = [-3, - 54 )

⇒ = -3, = - 54

∴ 2 + 4 = 9 - 5 = 4

Answer: (1)

JEE Main 2025 (Online) 3rd April Morning Shift

Keep practising — Relations and Functions

2

If the domain of the function f(x) = 7 (1 - 4 (x2 - 9x + 18 ) ) is ( , ) ( , ), then + + + is equal to

  1. 17
  2. 15
  3. 16
  4. 18
JEE Main 2025 (Online) 3rd April Evening Shift
3

Let A = \1, 2, 3, , 100\ and R be a relation on A such that R = \(a, b) : a = 2b + 1\. Let (a1, a2), (a2, a3), (a3, a4), , (ak, ak+1) be a sequence of k elements of R such that the second entry of an ordered pair is equal to the first entry of the next ordered pair. Then the largest integer k, for which such a sequence exists, is equal to :

  1. 6
  2. 8
  3. 7
  4. 5
JEE Main 2025 (Online) 2nd April Evening Shift
4

If the domain of the function f(x) = 1 10 + 3x - x2 + 1 x + |x| is (a, b), then (1 + a)2 + b2 is equal to :

  1. 29
  2. 30
  3. 25
  4. 26
JEE Main 2025 (Online) 2nd April Evening Shift
5

Let f : R R be a function defined by f(x) = (2 + 3a)x2 + ( a+2a-1 )x + b, a 1. If f(x + y) = f(x) + f(y) + 1 - 27xy, then the value of 28 i=15|f(i)| is

  1. 735
  2. 675
  3. 715
  4. 545
JEE Main 2025 (Online) 28th January Morning Shift

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