Ques. 1JEE Main 2025, 22 January (Evening Shift)
Let A=\1,2,3,4\ and B=\1,4,9,16\. Then the number of many-one functions f:A B such that 1 f(A) is equal to :
- 151
- 139
- 163
- 127
Answer
(1) 151
Solution
All functions 44=256; those missing 1: 34=81 1 f(A): 256-81=175
One-one = bijections =4!=24 (each contains 1)
many-one with 1 f(A) =175-24=151
Answer: (1)