If radius of the 2713Al nucleus is taken to be RAl, then the radius of 12553Te nucleus is nearly
- 35 RAl
- ( 1353 )1/3 RAl
- ( 5313 )1/3 RAl
- 53 RAl
Answer
(4) 53 RAl
Solution
As per NCERT, the radius of a nucleus of mass number A is R = R0A1/3
⇒ RTe RAl = ( 12527 )1/3
= 53
∴ RTe = 53 RAl
Answer: (4)