Two radioactive nuclei P and Q, in a given sample decay into a stable nucleus R. At time t = 0, the number of P species is 4N0 and that of Q is N0. Half-life of P (for conversion to R) is 1 minute whereas that of Q is 2 minutes. Initially there are no nuclei of R present in the sample. When number of nuclei of P and Q are equal, the number of nuclei of R present in the sample would be
- 2N0
- 3N0
- 9N02
- 5N02
Answer
(3) 9N02
Solution
After time t (in minutes):
NP = 4N0 ( 12 )t/1 and NQ = N0 ( 12 )t/2
For NP = NQ: 4 ( 12 )t = ( 12 )t/2
2t/2 = 4 t = 4 min
NP = NQ = 4N016 = N04
Total nuclei are conserved: NR = 5N0 - ( N04 + N04 )
= 9N02
Answer: (3)