Inverse Trigonometric Functions

JEE Main 2025 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 16% papers+4−1

Ques. 1JEE Main 2025, 24 January (Evening Shift)

If > > >0, then the expression -1 \ + (1+ 2)( - ) \+ -1 \ + (1+ 2)( - ) \ + -1 \ + (1+ 2)( - ) \ is equal to :

3
2-( + + )
0

Answer

(3)

Solution

Each bracket is one fraction: + 1+ 2 - = 1+ - , and similarly for the other two.

Term 1 and Term 2 are positive -1z= -1 1z:

( -1 - -1 )+( -1 - -1 )

Term 3 is negative ( < ) -1z= + -1 1z= + -1 - -1

Sum: the -1 parts cancel

Answer: (3)

Keep practising — Inverse Trigonometric Functions

Ques. 2JEE Main 2025, 23 January (Morning Shift)

If 2 x 3 4, then -1 ( 1213 x+ 513 x ) is equal to

x+ -1 512
x- -1 43
x+ -1 45
x- -1 512

Ques. 3JEE Main 2025, 22 January (Morning Shift)

Using the principal values of the inverse trigonometric functions, the sum of the maximum and the minimum values of 16 ( ( -1x )2+ ( cosec-1x )2 ) is :

24 2
18 2
22 2
31 2

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