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Motion in a Plane

JEE Main 2025 (Online) 24th January Evening ShiftMCQEasy📈 Topic in 3% papers+4−1
Ques. 1JEE Main 2025, 24 January (Evening Shift)

The position vector of a moving body at any instant of time is given as r= (5t2 i-5t j ) m. The magnitude and direction of velocity at t=2 s is,

  1. 5 17 m/s, making an angle of -14 with -ve Y axis
  2. 5 15 m/s, making an angle of -14 with +ve X axis
  3. 5 17 m/s, making an angle of -14 with +ve X axis
  4. 5 15 m/s, making an angle of -14 with -ve Y axis

Answer

(1) 5 17 m/s, making an angle of -14 with -ve Y axis

Solution

v= d rdt=10t i-5 j at t=2 s: v=20 i-5 j

[figure]

| v|= 202+52=5 17 m/s

= vx|vy|= 205=4: = -14 from the -ve Y axis

Answer: (1)

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Ques. 2JEE Main 2025, 23 January (Morning Shift)

Two particles are located at equal distance from origin. The position vectors of those are represented by A=2 i+3n j+2 k and B=2 i-2 j+4p k, respectively. If both the vectors are at right angle to each other, the value of n-1 is .

Ques. 3JEE Main 2025, 23 January (Evening Shift)

A ball having kinetic energy KE, is projected at an angle of 60 from the horizontal. What will be the kinetic energy of ball at the highest point of its flight?

  1. (KE)2
  2. (KE)8
  3. (KE)4
  4. (KE)16
Ques. 4JEE Main 2025, 22 January (Morning Shift)

A particle is projected at an angle of 30 from horizontal at a speed of 60 m/s. The height traversed by the particle in the first second is h0 and height traversed in the last second, before it reaches the maximum height, is h1. The ratio h0:h1 is . [Take, g=10 m/s2 ]

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