The position vector of a moving body at any instant of time is given as r= (5t2 i-5t j ) m. The magnitude and direction of velocity at t=2 s is,
- 5 17 m/s, making an angle of -14 with -ve Y axis
- 5 15 m/s, making an angle of -14 with +ve X axis
- 5 17 m/s, making an angle of -14 with +ve X axis
- 5 15 m/s, making an angle of -14 with -ve Y axis
Answer
(1) 5 17 m/s, making an angle of -14 with -ve Y axis
Solution
v= d rdt=10t i-5 j at t=2 s: v=20 i-5 j
[figure]
| v|= 202+52=5 17 m/s
= vx|vy|= 205=4: = -14 from the -ve Y axis
Answer: (1)