A projectile is fired at an angle of 45 with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is
- 45
- 60
- -1 ( 12 )
- -1 ( 32 )
Answer
(3) -1 ( 12 )
Solution
At the highest point the projectile is at height H and at horizontal distance R2 from the point of projection.
H = u2 2 2g and R2 = u2 g
= HR/2 = 2
For = 45 : = 12
= -1 ( 12 )
Answer: (3)