The hydrogen electrode is dipped in a solution of pH = 3 at 25 . The potential of the electrode will be − 10-2 V. ( 2.303RTF = 0.059 V )
Answer
18
Solution
Electrode reaction: 2H+(aq) + 2e- H2(g), E = 0, pH2 = 1 bar
Nernst equation: E = E - 0.0592 pH2[H+]2
= 0 - 0.059 pH
= -0.059 3 = -0.177 V
= -17.7 10-2 V ≈ -18 10-2 V
Answer: 18