Ques. 1JEE Main 2024, 29 January (Evening Shift)
Let the area of the region \(x, y): 0 x 3, 0 y \x2+2, 2x+2 \ \ be A. Then 12 A is equal to .
Answer
164
Solution
[figure]
x2+2 2x+2 0 x 2 (curves meet at (0, 2) and (2, 6))
upper boundary: y=x2+2 on [0, 2], y=2x+2 on [2, 3]
A= 02(x2+2) dx+ 23(2x+2) dx
= [ x33+2x ]02+ [x2+2x ]23= 203+7= 413
12A=164
Answer: 164