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If the circles (x+1)2+(y+2)2=r2 and x2+y2-4x-4y+4=0 intersect at exactly two distinct points, then
(2) 3<r<7
C1(-1,-2), r1=r; C2(2,2), r2= 4+4-4=2
C1C2= 32+42=5
two distinct common points |r1-r2|<C1C2<r1+r2
|r-2|<5 and r+2>5
-3<r<7 and r>3
3<r<7
Answer: (2)
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