A solid cylinder of mass M and radius R rolls without slipping down an inclined plane of length L and height h. What is the speed of its centre of mass when the cylinder reaches its bottom ?
- 2gh
- 34gh
- 43gh
- 4gh
Answer
(3) 43gh
Solution
For a solid cylinder: I = 12MR2 ⇒ K2R2 = 12
Energy conservation (no slipping ⇒ no work by friction): Mgh = 12Mv2 (1 + K2R2 )
⇒ gh = 12v2 32
⇒ v2 = 43gh
∴ v = 43gh
Answer: (3)