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The displacement and the increase in the velocity of a moving particle in the time interval of t to (t+1) s are 125 m and 50 m/s, respectively. The distance travelled by the particle in (t+2)th s is m.
175
Uniform acceleration: a= v t= 501=50 m/s2
In t t+1: 125=vt(1)+ 12(50)(1)2 vt=100 m/s
At t+1: v=100+50=150 m/s
Next second (t+1 t+2): s=150(1)+ 12(50)(1)2
=175 m
Answer: 175
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