The correct option with order of melting points of the pairs (Mn, Fe), (Tc, Ru) and (Re, Os) is :
- Fe < Mn, Ru < Tc and Re < Os
- Fe < Mn, Ru < Tc and Os < Re
- Mn < Fe, Tc < Ru and Re < Os
- Mn < Fe, Tc < Ru and Os < Re
Answer
(4) Mn < Fe, Tc < Ru and Os < Re
Solution
(Mn, Fe): Mn (3d5 4s2) has an exceptionally low melting point due to weak metallic bonding of the stable half-filled d5 set: Mn (1519 K) < Fe (1811 K)
(Tc, Ru): Tc (2430 K) < Ru (2607 K)
(Re, Os): In the 5d series the maximum lies at Re/W: Re (3459 K) > Os (3306 K) Os < Re
Mn < Fe, Tc < Ru and Os < Re
Answer: (4)