The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is 915 Å. The longest wavelength of spectral lines in the Balmer series will be Å.
Answer
6588
Solution
1 = R ( 1n12 - 1n22 )
Lyman shortest ( 1): 1915 = R
Balmer longest (3 2): 1 = R ( 14 - 19 ) = 5R36
= 365 915 = 6588 Å
Answer: 6588