Three particles, each of mass m gram, are situated at the vertices of an equilateral triangle ABC of side l cm (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC, in gram-cm2 units will be [figure]
- 34ml2
- 2ml2
- 54ml2
- 32ml2
Answer
(3) 54ml2
Solution
Distances of the particles from the axis AX:
A lies on the axis: rA = 0; B: rB = l; C (above the mid-point of AB): rC = l2
I = m(0)2 + ml2 + m ( l2 )2
= ml2 + ml24 = 54ml2
Answer: (3)