A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the plates of the capacitor. The glow of the bulb :
- becomes zero
- remains same
- increases
- decreases
Answer
(3) increases
Solution
A dielectric increases the capacitance (C' = KC), so XC = 1 C decreases.
Hence the impedance Z = R2 + XC2 decreases and the current I = VZ increases.
Therefore power in the bulb (I2R) increases and it glows brighter.
Answer: (3)