A series LCR circuit is subjected to an ac signal of 200 V, 50 Hz. If the voltage across the inductor (L = 10 mH) is 31.4 V, then the current in this circuit is .
- 10 A
- 10 mA
- 68 A
- 63 A
Answer
(1) 10 A
Solution
XL = 2 fL = 2 3.14 50 10 10-3
= 3.14
the same current flows through every element of a series circuit:
I = VLXL = 31.43.14 = 10 A
Answer: (1)