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Chemical Bonding and Molecular Structure · Question 30

JEE Main 2025 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 23% papers+4−1
1

Among SO2, NF3, NH3, XeF2, ClF3 and SF4, the hybridization of the molecule with nonzero dipole moment and highest number of lone-pairs of electrons on the central atom is

  1. sp3
  2. dsp2
  3. sp3d2
  4. sp3d

Answer

(4) sp3d

Solution

Lone pairs on the central atom and polarity:

SO2: 1 lp, bent polar

NF3, NH3: 1 lp each, pyramidal polar

XeF2: 3 lp, linear dipole moment zero (rejected)

ClF3: 2 lp, T-shaped polar

SF4: 1 lp, see-saw polar

The polar molecule with the most lone pairs is ClF3: 3 bond pairs + 2 lone pairs = 5 electron pairs sp3d.

Answer: (4)

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2

Which among the following molecules is (a) involved in sp3d hybridization, (b) has different bond lengths and (c) has lone pair of electrons on the central atom?

  1. XeF4
  2. XeF2
  3. PF5
  4. SF4
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3

An element 'E' has the ionisation enthalpy value of 374 kJ mol-1. 'E' reacts with elements A, B, C and D with electron gain enthalpy values of −328, −349, −325 and −295 kJ mol-1, respectively. The correct order of the products EA, EB, EC and ED in terms of ionic character is :

  1. EB > EA > EC > ED
  2. EA > EB > EC > ED
  3. ED > EC > EA > EB
  4. ED > EC > EB > EA
JEE Main 2025 (Online) 29th January Morning Shift
4

The sum of sigma ( ) and pi ( ) bonds in Hex-1,3-dien-5-yne is .

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5

The molecules having square pyramidal geometry are

  1. BrF5 & PCl5
  2. SbF5 & PCl5
  3. BrF5 & XeOF4
  4. SbF5 & XeOF4
JEE Main 2025 (Online) 28th January Morning Shift
6

Total number of molecules/species from the following which will be paramagnetic is . O2, O2+, O2-, NO, NO2, CO, K2[NiCl4], [Co(NH3)6]Cl3, K2[Ni(CN)4]

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