The value of n k=1n n3 (n2+k2 ) (n2+3k2 ) is :
- 8(2 3+3)
- (2 3+3) 24
- 13 8(4 3+3)
- 13(2 3-3) 8
Answer
(3) 13 8(4 3+3)
Solution
n3 (n2+k2 ) (n2+3k2 )= 1n 1 (1+ k2n2 ) (1+ 3k2n2 )
kn x, 1n dx (limit of a sum)
L= 01 dx (1+x2 ) (1+3x2 )= 12 01 [ 31+3x2- 11+x2 ]dx
= 12 [ 3 -1 ( 3x )- -1x ]01
= 12 [ 3 3- 4 ]
= (4 3-3 ) 24
= (4 3-3 ) (4 3+3 ) 24 (4 3+3 )= 39 24 (4 3+3 )= 13 8 (4 3+3 )
Answer: (3)