A system is taken from state a to state c by two paths adc and abc as shown in the figure. The internal energy at a is Ua = 10 J. Along the path adc the amount of heat absorbed dQ1 = 50 J and the work obtained dW1 = 20 J whereas along the path abc the heat absorbed dQ2 = 36 J. The amount of work along the path abc is [figure]
- 10 J
- 12 J
- 36 J
- 6 J
Answer
(4) 6 J
Solution
Along adc: = dQ1 - dW1 = 50 - 20 = 30 J
internal energy is a state function, is the same along abc.
Along abc: dW2 = dQ2 - = 36 - 30 = 6 J
Answer: (4)