PYQSide ExamsMy practice

Thermodynamics (Physics) · Question 31

NEET 2013 (Karnataka)MCQMedium📈 Topic in 25% papers+4−1
1

A system is taken from state a to state c by two paths adc and abc as shown in the figure. The internal energy at a is Ua = 10 J. Along the path adc the amount of heat absorbed dQ1 = 50 J and the work obtained dW1 = 20 J whereas along the path abc the heat absorbed dQ2 = 36 J. The amount of work along the path abc is [figure]

  1. 10 J
  2. 12 J
  3. 36 J
  4. 6 J

Answer

(4) 6 J

Solution

Along adc: = dQ1 - dW1 = 50 - 20 = 30 J

internal energy is a state function, is the same along abc.

Along abc: dW2 = dQ2 - = 36 - 30 = 6 J

Answer: (4)

NEET 2013 (Karnataka)

Keep practising — Thermodynamics (Physics)

2

Which of the following relations does not give the equation of an adiabatic process, where terms have their usual meaning?

  1. P1- T = constant
  2. PV = constant
  3. TV -1 = constant
  4. P T1- = constant
NEET 2013 (Karnataka)
3

Two Carnot engines A and B are operated in series. The engine A receives heat from the source at temperature T1 and rejects the heat to the sink at temperature T. The second engine B receives the heat at temperature T and rejects to its sink at temperature T2. For what values of T the efficiencies of the two engines are equal

  1. T1 - T22
  2. T1T2
  3. T1T2
  4. T1 + T22
NEET 2013 (Karnataka)
4

An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram. [figure] If Q1, Q2, Q3 indicate the heat absorbed by the gas along the three processes and U1, U2, U3 indicate the change in internal energy along the three processes respectively, then

  1. Q1 > Q2 > Q3 and U1 = U2 = U3
  2. Q3 > Q2 > Q1 and U1 = U2 = U3
  3. Q1 = Q2 = Q3 and U1 > U2 > U3
  4. Q3 = Q2 = Q1 and U1 > U2 > U3
AIPMT 2012 (Mains)
5

One mole of an ideal gas goes from an initial state A to final state B via two processes : It first undergoes isothermal expansion from volume V to 3V and then its volume is reduced from 3V to V at constant pressure. The correct P-V diagram representing the two processes is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2012 (Prelims)
6

A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is [figure]

  1. 2PV
  2. 4PV
  3. 12PV
  4. PV
AIPMT 2012 (Prelims)
7

A mass of diatomic gas ( = 1.4) at a pressure of 2 atmospheres is compressed adiabatically so that its temperature rises from 27 to 927 . The pressure of the gas in the final state is

  1. 8 atm
  2. 28 atm
  3. 68.7 atm
  4. 256 atm
AIPMT 2011 (Mains)
8

During an isothermal expansion, a confined ideal gas does 150 J of work against its surroundings. This implies that

  1. 150 J of heat has been removed from the gas
  2. 300 J of heat has been added to the gas
  3. no heat is transferred because the process is isothermal
  4. 150 J of heat has been added to the gas
AIPMT 2011 (Prelims)
9

When 1 kg of ice at 0 melts to water at 0 , the resulting change in its entropy, taking latent heat of ice to be 80 cal/g, is

  1. 273 cal/K
  2. 8 104 cal/K
  3. 80 cal/K
  4. 293 cal/K
AIPMT 2011 (Prelims)
10

If cp and cv denote the specific heats (per unit mass) of an ideal gas of molecular weight M, then

  1. cp - cv = RM2
  2. cp - cv = R
  3. cp - cv = RM
  4. cp - cv = MR
AIPMT 2010 (Mains)
11

A monatomic gas at pressure P1 and volume V1 is compressed adiabatically to 18th of its original volume. What is the final pressure of the gas?

  1. 64P1
  2. P1
  3. 16P1
  4. 32P1
AIPMT 2010 (Mains)

All Thermodynamics (Physics) PYQs →

PDFDownload Thermodynamics (Physics) PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All NEET Physics chapters