A monatomic gas at pressure P1 and volume V1 is compressed adiabatically to 18th of its original volume. What is the final pressure of the gas?
- 64P1
- P1
- 16P1
- 32P1
Answer
(4) 32P1
Solution
For a monatomic gas, = 53
Adiabatic process: P1V1 = P2V2 , with V2 = V18
P2 = P1 ( V1V2 ) = P1(8)5/3
= P1(23)5/3 = 25P1 = 32P1
Answer: (4)