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Kinetic Theory · Question 19

JEE Main 2025 (Online) 28th January Morning ShiftMCQEasy📈 Topic in 16% papers+4−1
1

For a particular ideal gas which of the following graphs represents the variation of mean squared velocity of the gas molecules with temperature?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(3) [figure]

Solution

Average kinetic energy of a molecule: 12m v2 = 32kBT

v2 = 3kBmT

For a particular gas m is fixed v2 T

The graph is a straight line through the origin.

Answer: (3)

JEE Main 2025 (Online) 28th January Morning Shift

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2

The ratio of vapour densities of two gases at the same temperature is 425, then the ratio of r.m.s. velocities will be :

  1. 52
  2. 254
  3. 425
  4. 25
JEE Main 2025 (Online) 28th January Evening Shift
3

The kinetic energy of translation of the molecules in 50 g of CO2 gas at 17 is :

  1. 4205.5 J
  2. 3582.7 J
  3. 3986.3 J
  4. 4102.8 J
JEE Main 2025 (Online) 28th January Evening Shift

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