1
A container of fixed volume contains a gas at 27 . To double the pressure of the gas, the temperature of gas should be raised to .
Answer
327
Solution
At constant volume: P1T1 = P2T2
T1 = 27 + 273 = 300 K, P2 = 2P1
T2 = 2T1 = 600 K
T2 = 600 - 273 = 327
Answer: 327
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