If R is the radius of the earth and the acceleration due to gravity on the surface of earth is g= 2 m/s2, then the length of the second's pendulum at a height h=2R from the surface of earth will be :
- 19 m
- 89 m
- 29 m
- 49 m
Answer
(1) 19 m
Solution
gh= g (1+ hR )2= g(1+2)2= 29 m/s2
a second's pendulum has T=2 s: 2=2 lgh
l= gh 2= 2/9 2
l= 19 m
Answer: (1)