Correct formula for height of a satellite from earth's surface is :
- ( T2R2g4 2 )1/3 - R
- ( T2R2g4 )1/2 - R
- ( T2R2g4 2 )-1/3 + R
- ( T2R24 2g )1/3 - R
Answer
(1) ( T2R2g4 2 )1/3 - R
Solution
T2 = 4 2GM(R + h)3
gravity gives the centripetal force: GMm(R + h)2 = m 2(R + h), and GM = gR2
(R + h)3 = T2R2g4 2
h = ( T2R2g4 2 )1/3 - R
Answer: (1)