D(+)-glucose reacts with hydroxylamine and yields an oxime. The structure of the oxime would be
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Answer
(4) [figure]
Solution
As per NCERT, glucose reacts with hydroxylamine to form an oxime; only the -CHO group (C-1) changes to -CH=NOH:
CHO-(CHOH)4-CH2OH NH2OH HON=CH-(CHOH)4-CH2OH
The configuration at C-2 to C-5 stays the same as in D-glucose (Fischer projection): -OH on the right at C-2, left at C-3, right at C-4 and right at C-5.
⇒ Order from top: H–C–OH, HO–C–H, H–C–OH, H–C–OH, which is structure (4).
Answer: (4)