In Young's double slit experiment, using monochromatic light of wavelength λ, the intensity of light at a point on the screen where the path difference is λ, is K units. The intensity of light at a point where the path difference is 3 will be :
- K
- 2 K
- K2
- K4
Answer
(4) K4
Solution
For two coherent waves of equal intensity, I = I0 2 2 and phase difference = 2 x
Path difference λ ⇒ = 2 ⇒ I = I0 2 = I0
I0 = K
Path difference 3 ⇒ = 2 3 ⇒ 2 = 60°
I = K 2 60° = K 14
I = K4
Answer: (4)