A submarine is designed to withstand an absolute pressure of 100 atm. How deep can it go below the water surface ? (Consider the density of water = 1000 kg m-3, 1 atm = 1 105 Pa and gravitational acceleration g = 10 m/s2)
- 9900 m
- 990 m
- 9000 m
- 99 m
Answer
(2) 990 m
Solution
Absolute pressure at depth h: P = P0 + gh
⇒ gh = P - P0 = (100 - 1) atm = 99 105 Pa
⇒ h = 99 1051000 10
= 990 m
Answer: (2)