Water flows in a streamline motion through a horizontal pipe of circular cross-section as shown in the figure. The pressure difference of water between P and Q is 15 N m-2. The area of cross-section at P and Q are 40 cm2 and 20 cm2, respectively. The rate of flow of water through the pipe, in cm3 s-1, is: [Take density of water = 1000 kg m-3] [figure]
- 400
- 100
- 200
- 300
Answer
(1) 400
Solution
By the equation of continuity:
AP vP = AQ vQ 40 vP = 20 vQ vQ = 2vP
Applying Bernoulli's theorem for a horizontal flow:
PP - PQ = 12 (vQ2 - vP2) = 12 (4vP2 - vP2) = 32 vP2
Substitute the given values:
15 = 32 1000 vP2 vP2 = 10-2 m2 s-2 vP = 0.1 m s-1 = 10 cm s-1
Rate of flow Q is:
Q = AP vP = 40 cm2 10 cm s-1 = 400 cm3 s-1
Answer: (1)