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Differential Equations · Question 10

JEE Main 2026 (Online) 2nd April Morning ShiftMCQEasy📈 Topic in 23% papers+4−1
1

If the curve y=f(x) passes through the point (1, e) and satisfies the differential equation dy=y (2+ e x )dx, x>0, then f(e) is equal to :

  1. ee
  2. ee2
  3. e2e
  4. e2e

Answer

(3) e2e

Solution

dyy=(2+ ex) dx

Integrating: ey=2x+(x ex-x)+C=x+x ex+C

At (1,e): 1=1+0+C C=0

ey=x(1+ ex)

At x=e: ey=e(1+1)=2e

∴ f(e)=e2e

Answer: (3)

JEE Main 2026 (Online) 2nd April Morning Shift

Keep practising — Differential Equations

2

Let y=y(x) be the solution curve of the differential equation (1+ x) dydx+(y+1) x=0, y(0)=0. If the curve y=y(x) passes through the point ( , -12 ), then a value of is :

  1. 6
  2. 4
  3. 3
  4. 2
JEE Main 2026 (Online) 2nd April Morning Shift
3

Let x=x(y) be the solution of the differential equation 2y2 dxdy-2xy+x2=0, y>1, x(e)=e. Then x (e2 ) is equal to:

  1. 32e2
  2. 23e2
  3. e2
  4. 2e2
JEE Main 2026 (Online) 2nd April Evening Shift
4

Let y = y(x) be the solution of the differential equation x dydx - 2y = x3 (2 - x3 ) 2 y, x 0. If y(2) = 0, then (y(1)) is equal to

  1. - 74
  2. - 34
  3. 34
  4. 74
JEE Main 2026 (Online) 28th January Morning Shift
5

Let y = y(x) be the solution of the differential equation x dydx - y = x2 x, x (0, ). If y ( 2 ) = 2, then 6y ( 6 ) - 8y ( 4 ) is equal to :

  1. -3
  2. 3
  3. -
JEE Main 2026 (Online) 28th January Evening Shift
6

Let a differentiable function f satisfy the equation 036 f ( tx36 )dt = 4 f(x). If y = f(x) is a standard parabola passing through the points (2, 1) and (-4, ), then is equal to .

JEE Main 2026 (Online) 24th January Morning Shift
7

Let y = y(x) be a differentiable function in the interval (0, ) such that y(1) = 2, and t x ( t2y(x) - x2y(t)x - t ) = 3 for each x > 0. Then 2y(2) is equal to :

  1. 27
  2. 18
  3. 23
  4. 12
JEE Main 2026 (Online) 24th January Evening Shift
8

Let y = y(x) be the solution of the differential equation x4 dy + (4x3y + 2 x) dx = 0, x > 0, y ( 2 ) = 0. Then 4 y ( 3 ) is equal to :

  1. 92
  2. 72
  3. 64
  4. 81
JEE Main 2026 (Online) 23rd January Morning Shift
9

Let f be a twice differentiable non-negative function such that (f(x))2 = 25 + 0x ((f(t))2 + (f'(t))2 )dt. Then the mean of f( e(1)), f( e(2)), , f( e(625)) is equal to .

JEE Main 2026 (Online) 23rd January Morning Shift
10

If the solution curve y = f(x) of the differential equation (x2 - 4)y' - 2xy + 2x(4 - x2)2 = 0, x > 2, passes through the point (3, 15), then the local maximum value of f is

JEE Main 2026 (Online) 23rd January Evening Shift
11

Let the solution curve of the differential equation x dy - y dx = x2 + y2 dx, x > 0, y(1) = 0, be y = y(x). Then y(3) is equal to

  1. 6
  2. 4
  3. 1
  4. 2
JEE Main 2026 (Online) 22nd January Morning Shift

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