The binding energy of deuteron is 2.2 MeV and that of 42He is 28 MeV. If two deuterons are fused to form one 42He then the energy released is
- 30.2 MeV
- 25.8 MeV
- 23.6 MeV
- 19.2 MeV
Answer
(3) 23.6 MeV
Solution
21H + 21H 42He
Energy released = B.E. of products − B.E. of reactants
= 28 - 2 2.2
= 23.6 MeV
Answer: (3)