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Application of Integrals · Question 29

JEE Main 2025 (Online) 28th January Morning ShiftMCQMedium📈 Topic in 74% papers+4−1
1

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803

Answer

(2) 643

Solution

The region is symmetric about the y-axis. For x 0: 0 y (2x + 1, x2 + 1).

x2 + 1 2x + 1 x(x - 2) 0 0 x 2

Area for 0 x 3 = 02(x2 + 1) dx + 23(2x + 1) dx

= [ x33 + x ]02 + [x2 + x ]23

= 143 + (12 - 6) = 323

Required area = 2 323 = 643

Answer: (2)

JEE Main 2025 (Online) 28th January Morning Shift

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2

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
JEE Main 2025 (Online) 28th January Evening Shift

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