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Hydrocarbons

JEE Main 2025 (Online) 23rd January Evening ShiftNumericalHard📈 Topic in 32% papers+4
Ques. 1JEE Main 2025, 23 January (Evening Shift)

A compound ' X ' absorbs 2 moles of hydrogen and ' X ' upon oxidation with KMnO4 | H+ gives [figure] The total number of bonds present in the compound ' X ' is .

Answer

27

Solution

2 mol H2 ⇒ X has two C=C; hot KMnO4/H+ cuts each C=C, so join the three products at their C=O ends:

[figure]

X = (CH3)2C=CH-CH2CH2-C(CH3)=CH-CH3 = C10H18

σ bonds = C–C + C–H = 9+18=27

Answer: 27

Keep practising — Hydrocarbons

Ques. 2JEE Main 2025, 22 January (Morning Shift)

Given below are two statements : In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both Statement I and Statement II are incorrect
  2. Statement I is incorrect but Statement II is correct
  3. Both Statement I and Statement II are correct
  4. Statement I is correct but Statement II is incorrect
Ques. 3JEE Main 2025, 22 January (Evening Shift)

When sec-butylcyclohexane reacts with bromine in the presence of sunlight, the major product is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2025, 22 January (Evening Shift)

The compound with molecular formula C6H6, which gives only one monobromo derivative and takes up four moles of hydrogen per mole for complete hydrogenation has electrons.

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All JEE Main Chemistry chapters
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Organic ChemistryOrganic Chemistry – Some Basic Principles and TechniquesIsomerismHydrocarbonsHaloalkanes and HaloarenesAlcohols, Phenols and EthersAldehydes, Ketones and Carboxylic AcidsAminesBiomoleculesPrinciples Related to Practical Chemistry