The ratio of escape velocity at earth (ve) to the escape velocity at a planet (vp) whose radius and mean density are twice as that of earth is
- 1 : 4
- 1 : 2
- 1 : 2
- 1 : 2 2
Answer
(4) 1 : 2 2
Solution
Escape velocity: v = 2GMR with M = 43 R3
⇒ v = 83 G R ⇒ v R
⇒ vevp = R2R 2 = 12 2
∴ ve : vp = 1 : 2 2
Answer: (4)