Let the inverse trigonometric functions take principal values. The number of real solutions of the equation 2 -1x + 3 -1x = 2 5, is .
Answer
0
Solution
For x [-1, 1]: -1x + -1x = 2
2 -1x + 3 -1x = 2 ( -1x + -1x ) + -1x = + -1x
+ -1x = 2 5 -1x = - 3 5
This is impossible because the principal value -1x [0, ].
Hence the number of real solutions = 0
Answer: 0