Imagine a new planet having the same density as that of earth but it is 3 times bigger than the earth in size. If the acceleration due to gravity on the surface of earth is g and that on the surface of the new planet is g', then
- g' = g/9
- g' = 27g
- g' = 9g
- g' = 3g
Answer
(4) g' = 3g
Solution
g = GMR2 = GR2 43 R3 = 43 G R
For the same density, g R
R' = 3R
g' = 3g
Answer: (4)