A cylinder is rolling down on an inclined plane of inclination 60 . Its acceleration during rolling down will be x 3 m/s2, where x= (use g=10 m/s2).
Answer
10
Solution
Rolling without slipping: a= g 1+ IMR2
Solid cylinder: IMR2= 12 a= 23g
a= 23 10 32= 10 3 m/s2
x=10
Answer: 10