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Oscillations

JEE Main 2024 (Online) 29th January Evening ShiftNumericalEasy📈 Topic in 2% papers+4
Ques. 1JEE Main 2024, 29 January (Evening Shift)

A simple harmonic oscillator has an amplitude A and time period 6 second. Assuming the oscillation starts from its mean position, the time required by it to travel from x=A to x= 32 A will be x s, where x= .

Answer

2

Solution

[figure]

Measuring time from the extreme P: x=A t

= 2 T= 2 6 = 13 rad s-1

32A=A t t= 6

t= /61/3= 2 s

x=2

Answer: 2

Keep practising — Oscillations

Ques. 2JEE Main 2024, 27 January (Morning Shift)

A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is cm, where = .

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