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When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is x8, where x= .
9
E= 12kA2, U= 12k ( A3 )2= E9
K=E-U= 8E9
EK= 98 x=9
Answer: 9
A simple harmonic oscillator has an amplitude A and time period 6 second. Assuming the oscillation starts from its mean position, the time required by it to travel from x=A to x= 32 A will be x s, where x= .
A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is cm, where = .