The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm, potential energy stored in it will be :
- 4U
- 8U
- 16U
- 2U
Answer
(3) 16U
Solution
U = 12kx2 U x2
U'U = ( 82 )2 = 16
U' = 16U
Answer: (3)
The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm, potential energy stored in it will be :
(3) 16U
U = 12kx2 U x2
U'U = ( 82 )2 = 16
U' = 16U
Answer: (3)
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