A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is :
- 5 J
- 25 J
- 20 J
- 30 J
Answer
(2) 25 J
Solution
For a variable force, W = 01 F dy
= 01 (20 + 10y) dy
= [20y + 5y2 ]01
= 20 + 5 = 25 J
Answer: (2)