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Conic Sections · Question 55

JEE Main 2026 (Online) 21st January Evening ShiftMCQMedium📈 Topic in 48% papers+4−1
1

Let one end of a focal chord of the parabola y2 = 16x be (16, 16). If P( , ) divides this focal chord internally in the ratio 5 : 2, then the minimum value of + is equal to:

  1. 5
  2. 7
  3. 22
  4. 16

Answer

(2) 7

Solution

y2 = 16x ⇒ a = 4; point (4t2, 8t)

(16, 16) ⇒ t1 = 2

Focal chord ⇒ t1 t2 = -1 ⇒ t2 = - 12 ⇒ other end (1, -4)

Case 1: P divides from (16, 16) to (1, -4) in 5 : 2

P = ( 5 + 327, -20 + 327 ) = ( 377, 127 ) ⇒ + = 7

Case 2: P divides from (1, -4) to (16, 16) in 5 : 2

P = ( 80 + 27, 80 - 87 ) = ( 827, 727 ) ⇒ + = 22

Minimum value of + = 7

Answer: (2)

JEE Main 2026 (Online) 21st January Evening Shift

Keep practising — Conic Sections

2

Let the ellipse 3x2 + py2 = 4 pass through the centre C of the circle x2 + y2 - 2x - 4y - 11 = 0 of radius r. Let f1, f2 be the focal distances of the point C on the ellipse. Then 6f1f2 - r is equal to

  1. 78
  2. 68
  3. 70
  4. 74
JEE Main 2025 (Online) 8th April Evening Shift
3

Let r be the radius of the circle, which touches x-axis at point (a, 0), a < 0 and the parabola y2 = 9x at the point (4, 6). Then r is equal to .

JEE Main 2025 (Online) 8th April Evening Shift
4

Let C1 be the circle in the third quadrant of radius 3, that touches both coordinate axes. Let C2 be the circle with centre (1, 3) that touches C1 externally at the point ( , ). If ( - )2 = mn, (m, n) = 1, then m + n is equal to

  1. 22
  2. 13
  3. 9
  4. 31
JEE Main 2025 (Online) 7th April Morning Shift
5

Let P be the parabola, whose focus is (-2, 1) and directrix is 2x + y + 2 = 0. Then the sum of the ordinates of the points on P, whose abscissa is -2, is

  1. 52
  2. 32
  3. 34
  4. 14
JEE Main 2025 (Online) 7th April Morning Shift
6

Consider the hyperbola x2a2 - y2b2 = 1 having one of its foci at P(-3, 0). If the latus rectum through its other focus subtends a right angle at P and a2 b2 = 2 - , , N, then + is .

JEE Main 2025 (Online) 7th April Morning Shift
7

Let the length of a latus rectum of an ellipse x2a2 + y2b2 = 1 be 10. If its eccentricity is the minimum value of the function f(t) = t2 + t + 1112, t R, then a2 + b2 is equal to :

  1. 115
  2. 120
  3. 125
  4. 126
JEE Main 2025 (Online) 7th April Evening Shift
8

Let e1 and e2 be the eccentricities of the ellipse x2b2 + y225 = 1 and the hyperbola x216 - y2b2 = 1, respectively. If b < 5 and e1 e2 = 1, then the eccentricity of the ellipse having its axes along the coordinate axes and passing through all four foci (two of the ellipse and two of the hyperbola) is :

  1. 45
  2. 35
  3. 74
  4. 32
JEE Main 2025 (Online) 7th April Evening Shift
9

Let p be the number of all triangles that can be formed by joining the vertices of a regular polygon P of n sides and q be the number of all quadrilaterals that can be formed by joining the vertices of P. If p + q = 126, then the eccentricity of the ellipse x216 + y2n = 1 is :

  1. 1 2
  2. 12
  3. 74
  4. 34
JEE Main 2025 (Online) 7th April Evening Shift
10

Let the lengths of the transverse and conjugate axes of a hyperbola in standard form be 2a and 2b, respectively, and one focus and the corresponding directrix of this hyperbola be (-5, 0) and 5x + 9 = 0, respectively. If the product of the focal distances of a point ( , 2 5) on the hyperbola is p, then 4p is equal to .

JEE Main 2025 (Online) 7th April Evening Shift
11

The length of the latus-rectum of the ellipse, whose foci are (2, 5) and (2, -3) and eccentricity is 45, is

  1. 503
  2. 185
  3. 65
  4. 103
JEE Main 2025 (Online) 4th April Morning Shift

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