If the system of equations x+2y-3z=2 2x+ y+5z=5 14x+3y+ z=33 has infinitely many solutions, then + is equal to :
- 13
- 10
- 12
- 11
Answer
(3) 12
Solution
Infinitely many solutions Eq.3 =p Eq.1+q Eq.2 (constants included).
x: p+2q=14; constant: 2p+5q=33 q=5, p=4
y: 2p+ q=3 8+5 =3 =-1
z: -3p+5q= =-12+25=13
+ =12
Answer: (3)