Two metal rods 1 and 2 of same lengths have same temperature difference between their ends. Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in 1 is four times that in 2, then
- K1A1 = 4K2A2
- K1A1 = 2K2A2
- 4K1A1 = K2A2
- K1A1 = K2A2
Answer
(1) K1A1 = 4K2A2
Solution
Rate of heat conduction: H = KA L
Same L and ⇒ H KA
H1 = 4H2
K1A1 = 4K2A2
Answer: (1)