The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is :
- 32
- 24
- 20
- 40
Answer
(2) 24
Solution
R=R0A1/3 R1R2= ( A1A2 )1/3
12= ( A1192 )1/3 A1192= 18
A1=24
Answer: (2)
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is :
(2) 24
R=R0A1/3 R1R2= ( A1A2 )1/3
12= ( A1192 )1/3 A1192= 18
A1=24
Answer: (2)
A nucleus has mass number A1 and volume V1. Another nucleus has mass number A2 and Volume V2. If relation between mass number is A2=4A1, then V2V1= .
In a nuclear fission reaction of an isotope of mass M, three similar daughter nuclei of same mass are formed. The speed of a daughter nucleus in terms of mass defect M will be :
The explosive in a Hydrogen bomb is a mixture of 1H2, 1H3 and 3Li6 in some condensed form. The chain reaction is given by 3Li6+0n1 2He4+1H3 1H2+1H3 2He4+0n1 During the explosion the energy released is approximately [Given ; M(Li)=6.01690 amu, M (1H2 )=2.01471 amu, M (2He4 )=4.00388 amu, and 1 amu=931.5 MeV]
In a nuclear fission process, a high mass nuclide (A 236) with binding energy 7.6 MeV/Nucleon dissociated into middle mass nuclides (A 118), having binding energy of 8.6 MeV/Nucleon. The energy released in the process would be MeV.
The atomic mass of 6C12 is 12.000000 u and that of 6C13 is 13.003354 u. The required energy to remove a neutron from 6C13, if mass of neutron is 1.008665 u, will be :